Proceed as for an equation (Attention: the inequality is reversed, if the two members are multiplied by a negative number !!) Or: Reduce to $ax + b$ in the first member, $0$ in the 2nd member, then use the discussion of the sign of$T = a x + b$ ------------------------------- If $a \lt 0$: $T \lt 0$ for $x \gt \frac {-b} {a}$ $T \gt 0$ for $x \lt \frac {-b} {a}$ ------------------------------- If $a \gt 0$ :: $T \gt 0$ for $x \gt \frac {-b} {a}$ $T \lt 0$ for $x \lt \frac {-b} {a}$ ------------------------------- If $a = 0$ :: $T$ has the sign of $b$ -------------------------------

Got it !

## Solve:

 $8x-6\gt 5+7x$ $12-5x \gt x-60$ $\frac{x}{2}+ 4 \gt \frac{2x}{3}- \frac{x}{8}$ $3-4(5-x) \leq 2x+5$ $\frac{x-2}{3}- \frac{1-x}{3}\geq 0$ $\frac{x}{3} -\frac{4-x}{4}\gt 5$ $2(x+1)\lt 3+2x$ $3(\frac{x}{2}-1)\gt \frac{3}{2}x- \frac{7}{3}$