Factorize trinomials by: $x^2+(a+b)x+ab = (x+a)(x+b)$:

Got it !

## Factorize:

 $x^2+5x+6 =$ $x^2+(2+3)x+2 \cdot 3 =(x+2)(x+3)$ $x^2-8x+12 =$ $x^2-4x-5 =$ $x^2+5x-14 =$ $x^3-4x^2-12x =$ $(x^2+16)^2-100x^2 =$ $2x-2-3x+3x^2+x^3-x^2 =$

## Simplify by factorizing :

 $\frac{x^2-2x-3}{9-x^2} =$ $\frac{x^2-7x-8}{x^3+3x^2+2x} =$ $\frac{x^3-x^2-4x+4}{x^2-3x+2} =$

## Solve equations :

 $\frac{x}{x^2+x-2}=\frac{1}{1-x}$ $\frac{x^2--7x+10}{x^2-25}= \frac{1}{2}$ $\frac{\frac{1}{x-1}}{\frac{1}{-3x+x^2+2}}=-1$