Equation with x to the denominator: The value of x must not reduce to zero the denominator !

Go !

 $\frac{3x-6}{x-3}= 2-\frac{3}{3-x}$ $x = 3 \qquad : \qquad S=\{ \}$ $\frac{x}{x+2}-\frac{1}{x-2}=\frac{2}{x+2}-\frac{x+2}{x^2-4}$ $(x-2)^2=0 \qquad;\qquad x = 2\qquad ;\qquad S =\{\}$