Calculate by the square trinomal formula : $(a ,\pm b)^2 = a^2 ,\pm 2ab + b^2$

Got it ! Perform and simplify:

$x(x+2)^2 =$	$x^3+4x^2+4x $
$(x+1)^2(x+2) =$	$x^3+4x^2+5x+2 $
$(x+1)^2-(x-1)^2 =$	$4x $
$[1-(2-x)]^2-x(x-2) =$	$1 $
$[x+(2x+1)^2-(2x)^2]^2 =$	$25x^2+10x+1 $
$[(56ax+23)^0]^2 =$	$ 1$