Reactions of alcohols with sodium

 

Find how many moles of Hydrogen are formed by the reaction of $ 6.4\;g $ of methanol with excess sodium! First look for the number of moles of methanol !

For answers, use (possibly multiple times) the arrows ↑ and ↓ at the top! Complete please this question before moving on to the next!

$n_{CH_3OH}$ $=$ $\frac{m}{M}$ $=$ $\frac{6,4}{32}$ $=$ $0.2\; mol$

Then the number of moles of hydrogen !

One mole (mono)alcohol produces $\frac{1}{2}$ molHydrogen, so: $n_{H_2}$ $=$ $\frac{0,2}{2}$ $=$ $0.1\; mol$